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9a^2-27a+20=0
a = 9; b = -27; c = +20;
Δ = b2-4ac
Δ = -272-4·9·20
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*9}=\frac{24}{18} =1+1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*9}=\frac{30}{18} =1+2/3 $
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